When a metal is burnt, its weight is increased by 24 percent. What will be the equivalent weight of the metal?
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Equivalent weight of O2O2 (oxide) ion is:
Molar mass of oxygen / charge on oxygen
=16gmol−1/2moleq−1=16gmol−1/2moleq−1
=8geq−1=8geq−1
One equivalent of the metal reacts with one equivalent of oxygen to form the metal oxide.
Let M be the equivalent weight of the metal,
Therefore, M grams of the metal will react with 8g of oxygen.
The corresponding metal oxide will or wWe can say that,
M=100×824M=100×824=33.33g
Molar mass of oxygen / charge on oxygen
=16gmol−1/2moleq−1=16gmol−1/2moleq−1
=8geq−1=8geq−1
One equivalent of the metal reacts with one equivalent of oxygen to form the metal oxide.
Let M be the equivalent weight of the metal,
Therefore, M grams of the metal will react with 8g of oxygen.
The corresponding metal oxide will or wWe can say that,
M=100×824M=100×824=33.33g
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6
Answer:
"Equivalent weight of O^2-(oxide) ion is : Molar mass of oxygen/ charge of oxygen
= 16 g mol^-1 /2 mol eq^-1
= 8 g eq^-1
Let us consider M to be the equivalent weight of the metal.
Therefore when M grams of the metal will react with 8g of oxygen the corresponding metal oxide formed will be 8gm more in Mass. This 8 gram is 24% of M.
Or we can say that M x 24/100 = 8 gram
So, M = 100 x 8/24 = 33.33 g
Explanation:
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