which term of an AP:6,13,20,27........is 98 more than its 24th term??
Answers
Answered by
59
24th term=6+23*7..
=167..
suppose x term is 98 more than its 24th termwhich is 167
xth term=6+(x-1)7
x term=167+98=265(becoz x is 98 more than 167)..
259=7(x-1)
x-1=37
x=38...
38 term of AP is 98 more than its 24th term.
:)
=167..
suppose x term is 98 more than its 24th termwhich is 167
xth term=6+(x-1)7
x term=167+98=265(becoz x is 98 more than 167)..
259=7(x-1)
x-1=37
x=38...
38 term of AP is 98 more than its 24th term.
:)
Answered by
104
Given Ap
is 6,13,20,27,......
first term =a=6
Common difference =d= t2-t1=13-6=7
nth term =tn=a+(n-1)d
Let pth term =t24+98
a+(p-1)7=a+(24-1)7+98
(p-1)7=23×7+98
(p-1)7=7(23+14)
p-1=37
p=38
Required term =38
is 6,13,20,27,......
first term =a=6
Common difference =d= t2-t1=13-6=7
nth term =tn=a+(n-1)d
Let pth term =t24+98
a+(p-1)7=a+(24-1)7+98
(p-1)7=23×7+98
(p-1)7=7(23+14)
p-1=37
p=38
Required term =38
Similar questions