when a metallic rod, conducting heat through it, is in thermal stedy state, the amount of heat passing through it in time t is given as q= kA(t1 - t2) t/L, where k=thermal conductivity of the material of the rod. A = cross sectional area of the rod, t1 and t2 are the temperatures of hot and cold ends, respectively, of the rod t= time and L= LENGTH of the rod obtain the dimensional formula for k.
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Joule=(k×m²×kelvin×sec)/m
K=Joule/(Kelvin ×sec ×m)
K=MLT(inverse) t(to the power-3)
T-temperature
t-time
K=Joule/(Kelvin ×sec ×m)
K=MLT(inverse) t(to the power-3)
T-temperature
t-time
Answered by
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Answer:
Joule=(k×m²×kelvin×sec)/m
K=Joule/(Kelvin ×sec ×m)
K=MLT(inverse) t(to the power-3)
T-temperature
t-time
Explanation:
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