Question

When a n object completes one and a half round around a circular path of diameter 7m,the distance covered and the displacement are

(2 Points)

66m and 7m

33m and 14m

7m and 66m

14m and zero


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Answer 1

Answer:

in one and half round

distance=circumference of circle+circumference of semicircle

$2\pi r + \pi r$

d=(2×3.14×3.5)+(3.14×3.5)

d=22+11=33

displacement=diameter

s=2×7=14

option b is correct

Explanation:

displacement is the shortest path between final and initial position

and distance is actual path travelled

note here diameter is given not radius read questions carefully

Answer 2

Answer:

When a person or a body moves along a path (circular or rectangular) and comes back to its initial position than the displacement of that body will be zero and distance travelled by body depend upon the revolution of body. So there athlete moves on circular path and travelled half of round that means travell half of the perimeter of the circle of radius 7 metre.

So in this case distance and displacement will be different

Let's calculate the distance travelled by the athlete

Distance =length of the perimetre of the circle multiplied by half

Distance=(22÷7)×radius

=(22÷7)×7

=22metre

Now displacement will be equal to the diameter of the circle that's 14metre

Explanation:

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