when a number is divided by 15,20,or 35,each time the remainder is 8.then the sallest number is
Answers
Answer:
Step-by-step explanation:
To calculate the smallest no. first, we will have to find LCM.
LCM of 15, 20, 35 = 420
420 is the number which is divisible by each three number given in the question. If we add 8 to 420, then no. becomes 428.
So 428 is the smallest number which gives the remainder 8 after divided by given three numbers.
Answer:
when a number is divided by 15,20,or 35,each time the remainder is 8.then the smallest number is 428
Step-by-step explanation:
To answer this question, let's get the LCM of the three numbers.
We do this by writing down the prime factors of each one of them.
We have:
15 = 3 × 5
20 = 2 × 2 × 5
35 = 5 × 7
The LCM of the three numbers is given by:
LCM = 2 × 2 × 5 × 3 × 7 = 420
420 is exactly divisible by 20, 35, and 35.
Since we have a remainder of 8 in each case, the smallest number in this case is given by:
= 420 + 8 = 428