Question

when a number is divided by 15,20,or35, each time the remainder is 8.then the smallest number is​

Answer 1

Answer:

First take LCM

The LCM is 900

then leaving remainder8

so,900-8=892

Answer 2

The smallest number is = 428

Step-by-step explanation:

Given numbers are 15, 20 and 35

the l.c.m of 15,20 and 35 =  420

Therefore the smallest number is = 420 +8 = 428 [ ∵ each time it leave 8 as remainder]