When a number is subtracted from the number 8,12 and 20, the remainders are in continued proportion, Find the number ?
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Let noBe (x) ex
8:12:20 =8:12:12::20(when there is three no. The middle one is became double
So, Proportion = 8-x:12-x::12-x:20-x
Product of extreme=product of means
(8-x)(20-x)=(12-x)(12-x)
160-8x-20x-x^2=144-x^2
-x^2 will be cut to -x^2
160-144= -8x-20x (transposing 144to
LHS)
16= 28x
x=16/28
x=4/7
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