Question

when a object is dropped from the surface of the earth, after 3 seconds what will be distance travelled by the object ?

Answer 1

There is a simple equation for this that is worth remembering, if only because it comes up in high school physics exams, and if you can’t remember how to derive it, well, at least you can still use it.

s=ut+12at2s=ut+12at2

s = the distance travelled, which is what we are trying to find

u = is the initial velocity, which is 0.

t = the elapsed time, which is 4

a = acceleration, which is g, or 9.80665 m per second per second

since u is 0, we simply have

s=129.80665×42=79.4532metress=129.80665×42=79.4532metres

Note that the height itself isn’t a factor, as long as it’s greater than 79.45 metres of course



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