Question

When a particle is thrown vertically upward it's velocity at one third of it's Max Height is 10√2 m/s The maximum height attained by it is

Answer 1

Answer:

Distance covered already = 1/3 H m = H/3 m

where, H = Max. Height

velocity at this point = u = 10 root 2 m/s

Remaining distance = H - H/3 = 2H/3 m

When the body reached H, velocity = 0

Acceleration = -g = -10 m/s^2

We know,

V^2 = u^2 + 2as

0 = (10 root 2)^2 + 2 × -10 × 2H/3

0 = 200 - 40H/3

40H/3 = 200

H/3 = 200/40 = 5

H = 5 × 3 = 15 m

Hence the max. height reached by body = 15 m.