Math, asked by devd80086, 10 months ago

The diameter of a road roller is 90cm and2m and 10cm in length.If it takes 400 revolutions to level a playground, find the cost of levelling the ground at 2.25 per square metre

Answers

Answered by neeru4112005

0

The values are different but the type of problem is same.....

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Answered by lovely06lucky

0

Step-by-step explanation:

circumference of road roller =2 pi(R-r)

=2*3.14*(50-45)m

=6.28*5m=31.4m

total distance covered = 400*31.4=12560m

total cost= Rs(12560*2.25)=Rs 28260

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