Question

when a particle of charge 20ampereC is brought from infinity to a point P,2.0mJ of work is done by the external force. what is the potential at P?

Answer 1

A body is starts at the rest,
∴ Initial Velocity of the body (u) = 0

Now, Distance covered b the body = 3 m.
Time taken by the body = 5 seconds.
∴ Velocity of the body = Distance/Time
= 3/5
= 0.6 m/s.
∴ Final Velocity (v) of the body = 0.6 m/s.


Now, Using the Formula,

∴
∴
∴ a = 0.12 m/s².


Hence, the acceleration of the body is 0.12 m/s².

Answer 2

Answer:

given,

q= 10 millicoulomb

or q= 10 x 10^-6 coulomb

w= 2.0 mJ

or w= 2 x 10^-3 joules

potential at point P = v= w/q

= 2 x 10^-3/ 10 x 10^6

= 2 x 10^2 v

therefore, potential at point P = 200v