Question

When a particle of mass m is suspended by a string of un-stretched length a, the string extends to

a length L . The particle is pulled down a small distance b and released. It then oscillates in

simple harmonic motion, derive a relation of w² (w is omega).​

Answer 1

Explanation:

Given:-

Unstretched length =  a

Total extended length = l

⇒ mg=K(l−a)

Now,

T = 2πKm

w=T2π

⇒  w2=l−ag