Question

When a point charge of 6mC is moved between two points in an electric field, the work done is 1.8 x 10-5 J. The potential difference between the two points is

Answer 1

Answer:

Electrostatic

Explanation:

★ Given ;

» Charge ( Q ) = 6 m c

» Work Done bye the system ( W ) = 1.8 × 10-⁵ J

» Potential Difference ( V ) = ???

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We Know that ;

Work Done = Charge ( Q ) × ∆ Potential Difference ( V )

V = W / Q

= 1.8 × 10-⁵ / 6 × 10-³

= 3 × 10-³ Or 3 m V

Potential difference ( V ) = + 3 m volt

Hope it helps you