when a polynomial 2x^3+3x^2+ax+b is divided by (x-2)leaves remainder 2and (x+2) leaves remaindr -2 find a and. b
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Step-by-step explanation:
a(x) ^3 +4(x)^2+3x-4
Now x=3 , put the value of x which is 3
f(3) = a(3) ^3 +4(3) ^2+3(3) -4... (i)
27a+36+9-4
27a+41=0....(ii)
(x) ^3-4(x)+a
3^3-4(3) +a
27-12+a
15+a=0....(iii)
As the remainder is same , we equate the eqs(ii) &(iii)
27a+41=15+a
26a=-26
a=-1
-1 is the answer... If iam not worng...
Hope the answer help you...
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