when a polynomial X square + 6 X + 9 is divided by( X + 3) of find the remainder
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Answer:
x^2+6x+9÷x+3
(x+3)×x=x^2+3x
x^2+6x+9-(x^2+3x)=3x+9
(x+3)×3=3x+9
3x+9-(3x+9)=0
therefore,remainder is 0
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This is your answer there is one more method to do that but it is easy than that method
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