Question

When a positively charged particle is projected with a velocity v0in the region between the horizontal

plates of the capacitor then it leaves by making an angle θ with the horizontal, as shown. If θ = θ₁ is
proton and θ = θ₂ for an α–particle then the value of (tanθ₁)/(tanθ₂).

Options and figure is in the attachment.​

Answer 1

Explanation:

I hope this is help full to you

Answer 2

Therefore, the value of $\dfrac{tan \; \theta_1}{tan \; \theta_2}$ is $\sqrt{2}$.

Refer to the attachments for the solution.