When a resistance R = 100 ohm is connected across terminals of the battery, a current I flows through it and when an additional unknown resistance is connected in series with R, a current 3I/4 flows through the battery. If the unknown resistance is connected in parallel with R , the battery current becomes 6I/5. Find the value of the unknown resistance.
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r1= 100
r2= ?
I 1= 31/4
I 2 = 61/5
1 ) v = r * I
v = 100 * 31/4
v= 400/4 * 31/4
4 = 124
124/4 = 31
v = 31
2) v = r * I
r = v / i
r = 31 / 61/5
r = 155/ 61
61 = 155
155- 61
r= 94
total resistance = r1+ r2
r = 100+94
r = 194 answer
r2= ?
I 1= 31/4
I 2 = 61/5
1 ) v = r * I
v = 100 * 31/4
v= 400/4 * 31/4
4 = 124
124/4 = 31
v = 31
2) v = r * I
r = v / i
r = 31 / 61/5
r = 155/ 61
61 = 155
155- 61
r= 94
total resistance = r1+ r2
r = 100+94
r = 194 answer
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