Physics, asked by ak165089, 2 months ago

When a screw gauge of the least count 0.01 mm is used to measure the diameter of the wire, the linear scale reading is 2 mm and 28th division of circular line coincides with the reference line. What is the diameter of the wire? If the screw gauge has a zero error of -0.04 mm, calculate the corrected diameter of the wire.​

Answers

Answered by pk0165161
1

Answer:

D

3.74mm

Zero error

Least count =0.02

Screw gauge reading

=−6×

50

1

mm=−0.12 mm

mm

=3+31×0.02 mm

=3.62 mm

Diameter of wire

=3.62 - Zeroerar

=3.62−(−0.12)

=3.74 mm

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