When a solid metallic sphere is heated the largest percentage increase occur in its?
Answers
Answered by
20
Volume is the answer you are looking for.
When a solid metallic sphere is heated, it expands and hence its radius also increases.
We know that for a sphere,
Volume =
and
Area = 4
Thus,
Volume
and
Area
Percentage change in volume:
ΔV/V = 3 Δr/r
Percentage change in Area:
ΔA/A = 2 Δr/r
Change in density:
Density decreases as on heating, the mass remains same but volume increases (Density = Mass/Volume)
Upon observation above, we see that Volume has the highest increase among all the physical quantities. Thus, Volume is the correct answer.
When a solid metallic sphere is heated, it expands and hence its radius also increases.
We know that for a sphere,
Volume =
and
Area = 4
Thus,
Volume
and
Area
Percentage change in volume:
ΔV/V = 3 Δr/r
Percentage change in Area:
ΔA/A = 2 Δr/r
Change in density:
Density decreases as on heating, the mass remains same but volume increases (Density = Mass/Volume)
Upon observation above, we see that Volume has the highest increase among all the physical quantities. Thus, Volume is the correct answer.
Answered by
8
Answer Is : Volume
Explanation:
⇒When a solid metallic sphere is heated, its diameter , surface area and volume will increases.
⇒As we know that density=mass/volume
⇒Here mass of the solid sphere remains unchanged . So its density decreases.
⇒Hence the percentage increase in its volume is greater because Coefficient of Volume expansion is greater than coefficient of area expansion and Linear expansion.
Explanation:
⇒When a solid metallic sphere is heated, its diameter , surface area and volume will increases.
⇒As we know that density=mass/volume
⇒Here mass of the solid sphere remains unchanged . So its density decreases.
⇒Hence the percentage increase in its volume is greater because Coefficient of Volume expansion is greater than coefficient of area expansion and Linear expansion.
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