when a springnis stretched by 2 cm, the energy stored is 100J
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I think You need to Find spring constant
According to Hookes law
PE = (KX^2)/2
100 =( K (0.02)^2)/2
200/0.0004 =K
K = 500000n/m
According to Hookes law
PE = (KX^2)/2
100 =( K (0.02)^2)/2
200/0.0004 =K
K = 500000n/m
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