Physics, asked by ammysinghg, 1 year ago

when a springnis stretched by 2 cm, the energy stored is 100J

Answers

Answered by Kundank
0
I think You need to Find spring constant

According to Hookes law

PE = (KX^2)/2
100 =( K (0.02)^2)/2
200/0.0004 =K
K = 500000n/m
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