Question

When a substances having mass 3 kg receives 600 cal of heat, it's temperature increases by 10°C .What is the specific heat of the substance?​

Answer 1

Conversion of mass in grams is necessary.

Hope it helps.. ...............

Answer 2

Answer:

Let the specific heat capacity of the substance be c.

We know, Mass of the substance, m = 3 kg = 3000 g

Heat given to the substance, Q = 600 cal

Increase in temperature of the substance = 10°C

Now, the amount of heat in a body is given as

Q = m × c × ΔT

⇒c = Q / m × ΔT = 600 / 3000 × 10 = 0.02 cal g−1 °C−1

= 0.0033 cal /(gm°C)