Question

When a tuning fork vibrates with 1.0 m or 1.05 m long wire of a sonometer, 5 beats per second are produced in each case. What will be the frequency of the tuning fork?(a) 195(b) 200(c) 205(d) 210

Answer 1

a}} 195

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Answer 2

Answer:

C) 205

Explanation:

Let the frequency of fork be = v

At the smaller length of sonometer wire ( L1= 1m), the frequency of wire should be higher, thus -

v1 = v+5

At the larger length of sonometer wire ( L2= 1.05m), the frequency of wire should be lower, thus-

v1 = v-5

Following the law of length = v1/v2 = L2/L1

v+5/v-5 = 1.05/1

v+5 = 1.05v-5.25

0.05v = 10.25

v = 10.25/0.05

v = 205

Thus the frequency of the tuning form will be 205 Hz