When a wire carries a current of 1.2 A, the drift speed is 1.2 × 10^-4 ms^-1. If the current in the wire is 6A, then the drift speed is
Answers
Explanation:
Answer :
A::D
Solution :
ltbr.<br> when current has increased fromto
Answer:
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Explanation:
Given
Initial current through the wire is I=1A
Initial drift velocity is, v d =1.2×10^−4 ms^ −1
Increased current is, I′ =5A
The current, I through the wire is given by
I=μe .e .A. v d
where, μe is the free electron density, e is the charge on electron, A is the area of cross section of the wire and v---d is the drift velocity of electrons.
Since, the free electron density, the charge on electron and the area of cross section of the wire are constant, hence
I ∝ v d :- (1)
Now, current though the wire is increased to 5 A, if the new drift velocity of electrons is v' d then
I′ ∝v' d :- (2)
From (1) and (2), we can write
v' d / v' d = I'/ I
v' d =I'/I v d
v' d = 5/1×1.2 ×10^−4
v' d =6×10^−4 ms ^−1