When a wire of length 10 m is subjected to a force
of 100 N along its length, the lateral strain
produced is 0.01 10-3 m. The Poisson's ratio
was found to be 04. If the area of cross-section of
wire is 0025 m. its Young's modulus is
Answers
Answered by
36
Answer:
1.6*10^8 Nm^-2
Explanation:
Poisson ratio = lateral strain /longitudianl strain.
I.e;
longitudianl strain. =lateral strain / Poissons ratio.
=0.01*10^-3/0.4
Young modules Y = normal stress / longitudianal strain
Y = F /A *(0.01*10^-3/0.4)
Y = 100 *0.4/0.025*0.01*10^-3 Nm^2
Y= 1.6*10^8 Nm^-2
Answered by
10
Answer:
1.6*10^8 Nm^-2
Explanation:
Poisson ratio = lateral strain /longitudianl strain.
I.e;
longitudianl strain. =lateral strain / Poissons ratio.
=0.01*10^-3/0.4
Young modules Y = normal stress / longitudianal strain
Y = F /A *(0.01*10^-3/0.4)
Y = 100 *0.4/0.025*0.01*10^-3 Nm^2
Y= 1.6*10^8 Nm^-2
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