When acetic acid treated with concern sulphuric acid?
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not sure about answer but I think CH3COOH + H2SO4 = CH3COOHSO4 + H2
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Concentrated H2SO4 can transfer one of its H+ to H3C-COOH, yielding protonated acetic acid:
H2SO4 + H3C-COOH → HSO4- + H3C-C(OH)OH+
This is the primary acid-base reaction that does occur, the H2SO4 acting as a Bronsted-Lowry acid and H3CCOOH acting as a base.
In principle you won’t get any water formed, because there is no hydroxide (MOH, M = metal) acting as a base.
PD: Water can be only formed if dehydration occurs. Dehydration is thus promoted by the H2SO4:
H3C-COOH + H3C-C(OH)OH+ → H3C-CO(O)CO-CH3 + H2O + H+
But strictly, water is not a product of the acid-base reaction between H2SO4 and acetic acid.
hope this will help you my friend.
H2SO4 + H3C-COOH → HSO4- + H3C-C(OH)OH+
This is the primary acid-base reaction that does occur, the H2SO4 acting as a Bronsted-Lowry acid and H3CCOOH acting as a base.
In principle you won’t get any water formed, because there is no hydroxide (MOH, M = metal) acting as a base.
PD: Water can be only formed if dehydration occurs. Dehydration is thus promoted by the H2SO4:
H3C-COOH + H3C-C(OH)OH+ → H3C-CO(O)CO-CH3 + H2O + H+
But strictly, water is not a product of the acid-base reaction between H2SO4 and acetic acid.
hope this will help you my friend.
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