Question

when ajit travelled 15 km , he found that one fourth of his journey was still left . What was the full length of the journey?​

Answer 1

Step-by-step explanation:

ANSWER:-

Given:-

• Given distance is 15km
• Also given 1/4th of his journey is left.
• We need to find the total journey length.

Concept:-

Addition of fractions and its properties.

Let's Do!

Let us consider the total distance as x (assumption)

So, according to question:-

$x - \dfrac{1}{4} x = 15$

So, we need to take its LCM or Lowest Common factor first.

$\dfrac{4x - x}{4} = 15$

$\dfrac{3x}{4} = 15$

$3x = 60$

$x = \dfrac{60}{3}$

x = 20 km is the required answer.

Question Twisted!

What if had said that it had covered 1/4th journey?

Then, we need to add 3/4 with 15, as :-

$1 - \dfrac{1}{4} \:$

$= \dfrac{4 - 1}{4}$

So, it gives us 3/4. And that's how the question was changed if this happened. (Most people do get confused in this, so that's it!)

*Edit- A minor Subtraction mistake converted to multiplication.

Answer 2

Given:-

$\bigstar$Ajit travelled 15 km

$\bigstar$¼ of his journey was still left

To Find:-

$\bigstar$Full length of the journey.

Solution:-

$\bigstar$Let us take total distance be x

$\\ \implies \tt \: x - \frac{1}{4} \times x = 15$

$\bigstar$Take LCM to make the denominator same.

$\\ \implies \tt \: \frac{x \times 4}{1 \times 4} - \frac{1}{4} \times x = 15$

$\\ \implies \tt \: \frac{4x - 1x}{4} = 15$

$\\ \implies \tt \: \frac{3x}{4} = 15$

$\\ \implies \tt \: 3x = 15 \times 4$

$\\ \implies \tt \: 3x = 60$

$\\ \implies \tt \: x = \frac{60}{3}$

$\\ \implies \tt \: x = 20$

$\bigstar$Hence, the full length of the journey is 20 km.