Question

write the Ring structure of glucose ​

Answer 1

Explanation:

Glucose (C6H12O6) is a hexose -- a monosaccharide containing six carbon atoms. Glucose is an aldehyde (contains a -CHO group). Five of the carbons plus an oxygen atom form a loop called a "pyranose ring", the most stable form for six-carbon aldoses.

I think this will be the answer.

Answer 2

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On the basis of chemical evidence stereostructure of D-glucose was represented by the Fischer projection formula IGlucose, however, was found to exhibit some more chemical properties which could not be explained on the basis of the structure I. It was necessary to write another structure for glucose which will explain all the properties. Ring structure of glucose fulfils this requirement Glucose is found to have two cyclic structures (VI and VII) which are in equilibrium with each other through the open chain structure (I) in aqueous solution

The ring structure of glucose is formed by reaction between the formyl (-CHO) group and the alcoholic (-OH) group at C-5. Thus, the ring structure is a hemiacetal structure.The two hemiacetal structures (VI and VII) differ only in the configuration of C-1 the additional chiral centre resulting from ring closure. The two ring structures are called ∝- and β- anomers of glucose and C-1 is called the anomeric carbon. The ring of the cyclic structure of glucose contains five carbons and one oxygen. Thus, it is a six membered ring. It is called pyranose structure, in analogy with the six membered heterocyclic compound pyran . Hence glucose is also called glucopyranose. Haworth formula is a better way than Fischer projection formula to represent structure of glucopyranose. In the Haworth formula the pyranose ring is considered to be in a perpendicular plane with respect to the plane of paper. The carbons and oxygen in the ring are in the places as they appear in The lower side of the ring is called ∝-side and the upper side is the β-side. The ∝-anomer has its anomeric hydroxyl (-OH) group (at C-1) on the ∝-side, whereas the β-anomer has its anomeric hydroxyl (-OH) group (at C-1) on the β-side. The groups which appear on right side in the Fischer projection formula appear on a-side in the Haworth formula, and viceversa