Question

When aluminum metal is dipped ina solution ofhydrochloric acid them hydrogen gas is evolved with the formation of aluminium chloride solution what is the equation

Answer 1

Hey there!

Here is the equation you are looking for:-

2Al (s) + 6HCl (aq) -------> 2AlCl3 (aq) + 3H2 (g)


_________________________

Hope it cleared your query.

Answer 2

Answer:

1 min

Explanation:

This reaction is between a metal and an acid which typically results in a salt and the release of hydrogen gas. The unbalanced reaction is

Al + HCl -> H_2 + AlCl_3

A

l

+

H

C

l

→

H

2

+

A

l

C

l

3

.

This is a redox reaction, whose half-reactions are and become:

2("Al"(s) -> "Al"^(3+)(aq) + cancel(3e^(-)))

3(2"H"^(+)(aq) + cancel(2e^(-)) -> "H"_2(g))

"-----------------------------------------------"

2"Al"(s) + 6"H"^(+)(aq) -> 3"H"_2(g) + 2"Al"^(3+)(aq)

Aluminum oxidizes as "Al" -> "Al"^(3+), while hydrogen reduces as 2"H"^(+) -> "H"_2^0.

If we add back the spectator "Cl"^(-), we get:

color(blue)(2"Al"(s) + 6"HCl"(aq) -> 3"H"_2(g) + 2"AlCl"_3(aq))