When an aeroplane took off, it was noted that for every 100 m rise in altitude, the temperature dropped by 1.5 degree celcius. The plane reached an altitude 25 times the distance of 100 m , by how much the temperature would have dropped if the ground temperature was 27.5 degree celcius?
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Step-by-step explanation:
T drop rate = 1.5°C / 100m
distance covered = 100×25=2500m
this means 25 tines tge temperature had dropped for 1.5°C.
total temparature drop = 1.5×25=37.5°C
ground temparature= 27.5 °C
∆T= (27.5-37.5)°C = -10°C ......(ans)
hope it helps ......T means temparature and ∆T means actual temperature(initian T- final T)
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