Question

When an aeroplane took off, it was noted that for every 100 m rise in altitude, the temperature dropped by 1.5 degree celcius. The plane reached an altitude 25 times the distance of 100 m , by how much the temperature would have dropped if the ground temperature was 27.5 degree celcius?

Answer 1

Step-by-step explanation:

T drop rate = 1.5°C / 100m

distance covered = 100×25=2500m

this means 25 tines tge temperature had dropped for 1.5°C.

total temparature drop = 1.5×25=37.5°C

ground temparature= 27.5 °C

∆T= (27.5-37.5)°C = -10°C ......(ans)

hope it helps ......T means temparature and ∆T means actual temperature(initian T- final T)

pplzzz mark brainliest