When an element forms an oxide in which oxygen is 20% of the oxide by mass, the equivalent mass of the element will be :
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Let the total amount of oxide be 100
∴∴ mass of oxygen is 20
∴∴ mass of element is (100-20)=80
∴∴ equivalent mass of element=massofelementmassofoxygenmassofelementmassofoxygen×8×8
=8020=8020×8×8
=32=32
Hence (b) is the correct option
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