Physics, asked by harshitsingh1320, 10 months ago

When an object is allowed to slide down a hill it stops at the point b because of friction. If friction force depends only on the normal component of the reaction force with coefficient of friction variable along the path, the work done in taking the object slowly from b to a along the hill will be?

Answers

Answered by mithless670
0

Answer:

Explanation:

The question is explained in the image attached with the this . The body is moving down an inclined pane .

Attachments:
Answered by Anonymous
0

Due to friction, when an object is able to move down a hill it stops at point b, the work done in slowly taking the object from b to a will is equal to the object's mass.

  • Frictional forces are proportional with the forces pressing the surfaces. The force affecting frictional resistance is the component of applied force that acts perpendicularly to the contact surfaces and is typically referred to as normal force.
  • Because the friction force depends only on the normal portion of the reaction, the normal for is nothing but the body's weight. Therefore, if no other external factors intervene, the work done to slowly take the object back to the point will be equal to the body's weight.
  • The frictional forces are proportional to the pushing forces on the surfaces. The force causing frictional resistance is the part of the force applied that acts perpendicularly or "normally" to the contact surfaces and is usually called normal force.
Similar questions