Question

When an object is dropped from the height of 100m from the surface of the earth after 3 seconds what will be the distance travelled by the object?

Answer 1

$a = 9.8\frac{m}{ {s}^{2} } \\ t = 3s \\ u = 0$
distance travelled
$s = ut + \frac{1}{2} a {t}^{2}$
$0 + \frac{1}{2} \times 9.8 \times {3}^{2}$
44.1m

Answer 2

According to the formula,

S= ut+ 1/2 gt^2

where S= Distance travelled ( we need to find this)

u- initially velocity( here it is zero)

t= 3 seconds

g- acceleration due to gravity ( 9.8m/s^2)

Here, the height given as 100m is irrelavant and not required in the calculation of distance.

So, putting the values in the given formula:

S= 0 + 1/2 × 9.8 × 3 × 3

= 44.1 m

Therefore, the distance travelled by the object is 44.1 m.