When an object is placed at a distance of 50 cm from a concave mirror,the magnification produced is -1/2.where should the object be placed to get a magnification of -1/5
full solution plzz
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u = - 50 (since u is always negative)
magnification = -1/2
new magnification = - 1/5
new u = ?
m= -v/u
- 1/2= -v/-50
-1/2* - 50= -v
25 = -v
v = 25
1/f= 1/v +1/u
1/f= 1/25+1/-50
1/f= 2-1/50
1/f= 1/50
f = -50 (f is negative for concave mirror)
m = f/ f-u
-1/5= - 50/ -50-u
-1/u=1/5
u = -5 cm
where should the object be placed to get a magnification of -1/5= - 5 cm
hope this helps u
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