Question

when an object of 10 kg is lifted through 3M by the application of force the work done by the applied force is

Answer 1

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$\underline\bold\red{\huge{ANSWER : }}$

⭐ Mass of the object given (m) = 10 kg.

⭐ Height acquired by the object (h) = 3 m.

⭐ We know, acceleration due to gravity (g)
= 9.8 m/s².

⭐ Therefore, work done by the applied force

= mgh
= (10×3×9.8) Joule
= 294 Joule {Ans.}


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Answer 2

Mass of the object given (m) = 10 kg. 

Height acquired by the object (h) = 3 m. 

We know, acceleration due to gravity (g) 
= 9.8 m/s². 

Therefore, work done by the applied force

= mgh
= (10×3×9.8) Joule
= 294 Joule {Ans.}