When an object of height 1 cm is placed in front of a lens, the image formed is real, inverted and of height 2cm. The distance between the image and object is 90 cm. Find, the focal length of the lens used.
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Answer:
Let, image distance=v
object distance=u
v+u=90 cm
or, v=90-u
Here,
Height of the image/Height of the object=Image distance/Object distance
or, 2/1 = v/u
or, 2/1 = (90-u)/u
or, 2 u = 90-u
or, 3 u = 90
∴ u= 30 cm
∴ v = 90 - u = 90 - 30 = 60 cm
Now,
Using lens formula,
1/f = 1/u + 1/v
or, 1/f = 1/30 + 1/60
or, 1/f = 3/60
or, 1/f = 1/20
∴ f = 20 cm
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