When an observer at a distance of 12 m from a tree looks at the top of the tree , the angle of elevation is 60 degree. What is the height of the tree?
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According to question ,
let , ABC is a right angle triangle
angle B = 90°, AB = h , BC = 12 m
so,
tan60° = AB/BC
√3= h/12
h. = 12√3m ans
putting the value of √3
h = 12*1.73
= 20.76m ans
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