Chemistry, asked by chanikya135, 11 months ago

When B H2 6 reacts with excess ammonia at room temperature, select correct about
product.
1. Both boron are bonded with nitrogen
2. One of the boron is bonded with nitrogen
3. None of the boron is bonded with nitrogen
4. B H2 6 does not react with ammonia at low temperature

Answers

Answered by Itzraisingstar
2

Answer:

Explanation:

When diborane is heated with excess ammonia, it reacts with ammonia to form borazine and hydrogen.

"This reaction takes place at a high temperature of 180-190˚C". This reaction of diborane and ammonia is considered to be highly complex in nature. Diborane is majorly used as rocket propellants and also as a reducing agent.  

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Answered by prashant12330
2

Explanation:

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mindfulmaisel Ace

When diborane is heated with excess ammonia, it reacts with ammonia to form borazine and hydrogen.

"This reaction takes place at a high temperature of 180-190˚C". This reaction of diborane and ammonia is considered to be highly complex in nature. Diborane is majorly used as rocket propellants and also as a reducing agent.

The chemical equation for the reaction is:

\mathrm{B}_{2} \mathrm{H}_{6}+\mathrm{NH}_{3} \rightarrow \mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}+\mathrm{H}_{2}

The balanced equation for the reaction is:

3 \mathrm{B}_{2} \mathrm{H}_{6}+6 \mathrm{NH}_{3} \rightarrow 2 \mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}+12 \mathrm{H}_{2}

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