When Benzyl Trimethyl Ammonium Chloride react with Naoet then what product formed
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When Benzyl Trimethyl Ammonium Chloride react with Naoet then what product formed
Answer ↘️
The E1 and E2 elimination mechanisms can also be distinguished by a primary deuterium isotope effect, which measures the degree to which C—H and C—D bonds are broken in the rate-determining step. The carbon-hydrogen bond is slightly weaker than the carbon-deuterium bond. If a C—H bond is broken in a rate-determining step, then the corresponding C—D bond in the isotopically substituted compound would require more energy to reach the transition state. The deuterium-labeled compound therefore would react at a slower rate. If a C—H (or C—D) bond cleavage occurs in a fast step after the rate-determining step, the rates would be the same. This means that we can distinguish between the E2 and El reactions by placing deuterium where it can be abstracted by a base. For example, the rates of dehydrobromination of 1-bromo-2-phenylethane and l-bromo-2,2-dideuterio-2-phenylethane differ by a factor of seven.