Chemistry, asked by tayab9607, 9 months ago

When Br₂ is treated with aqueous solutions of NaF, NaCl
and NaI separately
(a) F₂, Cl₂ and I₂ are liberated
(b) only F₂ and Cl₂ are liberated
(c) only I₂ is liberated
(d) only Cl₂ is liberated

Answers

Answered by chemisst
0

When Br₂ is treated with aqueous solutions of NaF, NaCl  and NaI separately only I₂ is liberated.

Explanation:

When Br₂ is treated with aqueous solutions of NaF, NaCl  and NaI separately only iodine is liberated because the reactivity of bromine is less than fluorine and chlorine so it can not displace them. When bromine react with sodium iodide it displaces the iodine because its reactivity is more than iodine.

Chemical reaction:

Br₂ + 2NaI  →  I₂ + 2NaBr

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