Question

WHEN BRAKES ARE APPLIED IN A TRAIN IT
PRODUCED A RETARDATION OF 5m/SEC AND
STOPPED IN 3 SEC. CALCULATE THE
DISTANCE TRAVELLED BY THE TRAINAFTER
THE BRAKES WERE APPLIED​

Answer 1

Explanation:

a=-5m/s²

t=3sec

v=0m/s

s=?

for finding distance we have to find initial velocity

v=u+at

0=u+(-5)X3

-u=-15

u=15m/s

s=ut+1/2 at^2

s=15X3+1/2X(-5)X(3)²

s=45+(-45/2)

s=45-22.5

s=22.5