When brakes are applied to a uniform velocity of 72km/hr it comes to a stop after covering a distance of 50m determine retardation of the car and the time taken by it to stop
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U=initial speed=72km/h=20 m/sec.
v=final speed =0 km/h
time=t= 5 sec.
v=u+at
v-u=at= v-u/t=a
-20/5= -4 m/sec^2 = deacceleration
now using the eqn:-
S=ut+1/2 a
S=20*5 + (-4) * 5*5
S=100 - 50 =50 m.
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