When Ca(NO3)2 is heated, it gives CaO, NO2(8)
and O2(g). The correct number of moles of
Ca(NO3)2, CaO, NO2(g) and O2(g) are present
in the reaction are respectively
21.3.2
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Therefore, 65.6 g produces = (65.6*112)/328 = 22.4 g CaO. 4) - Given the stoichiometric coefficients, we know 5 moles of gaseous products are already being produces ( 4+1) by 2 moles of reactant. 5) - 44.8 L at STP = 2 moles of NO2, since One mole of any gas at S.T.P.
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Answered by
11
Answer:
2,2,4,1
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