Question

When car s covered a distance of d on a track, it covered 25% more distance than car t had covered on the same track.

Answer 1

Answer:

what is asked in the question kindly edit the q.

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Answer 2

Distance covered by car T is 0.8d .

Given :

Distance covered by car S is d .

Let , distance covered by car T is x .

Now , it is also given that the distance covered by car S is 25 % more than the   distance covered by car T .

We need to find the distance covered by the car T .

Therefore ,

$d=x+\dfrac{25}{100}x\\\\d=\dfrac{125}{100}x\\\\x=\dfrac{4}{5}d\\\\x=0.8d$

Therefore , distance covered by car T is 0.8d .

Hence , this is the required solution .

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