When CH₂ = CH — COOH is reduced with LiAlH₄, the compound obtained will be
(a) CH₂ = CH — CH₂OH
(b) CH₃ — CH₂ — CH₂OH
(c) CH₃ — CH₂ — CHO
(d) CH₃ — CH₂ — COOH
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CH₂ = CH — COOH is reduced with LiAlH₄, the compound obtained will be
(a) CH₂ = CH — CH₂OH
(b) CH₃ — CH₂ — CH₂OH
(c) CH₃ — CH₂ — CHO
(d) CH₃ — CH₂ — COOH
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