When CH₃CH₂CHCl₂ is treated with NaNH₂ , the
product formed is
(a) CH₃ — CH = CH₂
(b) CH₃—C ≡ CH
NH₂
/
(c) CH₃CH₂CH
∖
NH₂
Cl
/
(d) CH₃CH₂CH
∖
NH₂
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option b is the correct answer
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Answer:
option b.... Hope help you xd brainlist plz
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