Chemistry, asked by devanandprasad8554, 10 months ago

When CH₃Cl and AlCl₃ are used in Friedel-Crafts reaction, the electrophile is
(a) Cl⁺
(b) $AlCl_4^-$
(c) $CH_3^+$
(d) $AlCl_2^+$

Answers

Answered by gopuajay370

0

Option C is correct as alcl3 helps 9n formation of CH3+ electrophile

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