when circular scale of a screw gauge carrying hundred divisions is given for complete rotation is the head of the screw moves through to 2MM calculate pitch and least count of screw gauge
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↪Here number of divisions on circular scale = 100
↪Number of complete rotation = 4
↪Distance moved = 2 mm
↪Pitch = Distance moved / Number of complete rotations
↪2mm / 4
↪0.5 mm
↪Least count = Pitch / Number of divisions on circular scale .
↪0 . 5mm / 100
↪0.005mm
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____________________________________________
↪Here number of divisions on circular scale = 100
↪Number of complete rotation = 4
↪Distance moved = 2 mm
↪Pitch = Distance moved / Number of complete rotations
↪2mm / 4
↪0.5 mm
↪Least count = Pitch / Number of divisions on circular scale .
↪0 . 5mm / 100
↪0.005mm
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