When copper is treated with a certain
concentration of nitric acid, nitric oxide and
nitrogen dioxide are liberated in equal volumes
according to the equation
XCu + PHNO, Cu(NO,), + NO + NO, + H,O
The coefficients x and y are
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Answer: 1 and 4
Explanation:
the actual reaction with coefficients,
reaction 1 .... 1Cu + 4HNO3 ====> Cu(NO3)2 + 2NO +2H2O
where we have nitic oxide , water and copper nitrate as our products
BY COMPARISON ,
X= 1 and Y = 4
(i hope it was 'y' and not 'P')
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