Question

when current in a coil changes from 6A to 2A in 0.1s , and value of induced e.m.f is 40v . what is the self- inductance of the coil ?​

Answer 1

Answer:

1H

Explanation:

v = L di/dt

-40 = L 2-6/0.1

-40 = L -4×10

-40 = -40L

L = 1H

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