When dil.h2SO4 is electrolysed 5.6 of h2 is liberated at cathode. Calculate the volume of O2 liberated at anode?
Answers
Answered by
0
We know, when acidifed H2O is hydorlysed, the rxn. is
2H2O---->2H2+O2
i.e 2moles of H2 and 1 mole of O2 is liberated.
therefore, if 5.6 L H2 is liberated at cathode, 2.8 L oxygen will be liberated at anode.
Similar questions